loops - Python code to count vowels -



loops - Python code to count vowels -

assume s string of lower case characters.

write programme counts number of vowels contained in string s. valid vowels are: 'a', 'e', 'i', 'o', , 'u'. example, if s = 'azcbobobegghakl', programme should print:

number of vowels: 5

i have far

count = 0 vowels = 'a' or 'e' or 'i' or 'o' or 'u' vowels in s: count +=1 print ('number of vowels: ' + count)

can tell me wrong it?

a couple of problems. first, assignment vowels doesn't think does:

>>> vowels = 'a' or 'e' or 'i' or 'o' or 'u' >>> vowels 'a'

python evaluates or lazily; of predicates evaluates true returned. non-empty sequences, including strings other "" evaluate true, 'a' returned straight away.

second, when iterate on s, ignore assignment anyway:

>>> vowels in "foo": print(vowels) f o o

for x in y: assigns each item in iterable y name x in turn, assigned x not longer accessible via name.

i think want is:

count = 0 vowels = set("aeiou") letter in s: if letter in vowels: count += 1

python loops

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