c# - Reading XML Nodes -



c# - Reading XML Nodes -

i have next xml file. trying read startdate node of dept element don't want read "startdate" node of of rest of kid elements "deptroles".

<dept operationalstatus="active" primaryrole="admin" depchangedate="20130420"> <startdate type="legal">20130401</startdate> <enddate type="legal"></enddate> <startdate type="operational">20130320</startdate> <enddate type="operational"></enddate> <deptroles> <deptrole name="other dept" status="active"> <startdate type="legal">20130401</startdate> <enddate type="legal"></enddate> <startdate type="operational">20130320</startdate> <enddate type="operational"/> <isprimary/> </deptrole> </deptroles> </dept>

this c# code. code getting deptrole startdate element, dont want.

public static list<organisation> getorgdata(string data) { list<organisation> listorgdata = new list<organisation>(); xmlreader xmlreader = xmlreader.create(new stringreader(data)); while (xmlreader.read()) { if (xmlreader.nodetype == xmlnodetype.element) { organisation record = new organisation(); if (xmlreader.hasattributes && xmlreader.name == "dept") { record.orgoperationalstatus = xmlreader.getattribute("operationalstatus"); record.orglegalstatus = xmlreader.getattribute("legalstatus"); } else if (xmlreader.name == "name") { record.orgname = xmlreader.readelementstring("name"); } else if (xmlreader.name == "startdate" || xmlreader.name == "enddate") { if (xmlreader.getattribute("type") == "legal") { record.orglegalstartdate = xmlreader.readelementstring("startdate"); record.orglegalenddate = xmlreader.readelementstring("enddate"); } else if (xmlreader.getattribute("type") == "operational") { record.orgoperationalstartdate = xmlreader.readelementstring("startdate"); record.orgoperationalenddate = xmlreader.readelementstring("enddate"); listorgdata.add(record); } } } } homecoming listorgdata; }

i utilize linq xml (as others have suggested). below sample code matches posted code - explanation of code follows.

public static list<organisation> getorgdata(string data) { list<organisation> listorgdata = new list<organisation>(); xdocument xdoc = xdocument.parse(data); listorgdata = xdoc.root.elements("dept") .select(x => new organisation() { orgoperationalstatus = (string)x.attribute("operationalstatus"), orglegalstartdate = (string)x.elements("startdate") .where(x1 => (string)x1.attribute("type") == "legal") .first(), orgoperationalstartdate = (string)x.elements("startdate") .where(x1 => (string)x1.attribute("type") == "operational") .first() }).tolist(); homecoming listorgdata; }

the first thing above code load xml xdocument xdocument.parse method.

the query parses xml document , returns list of populated organization objects. goes this.

get <dept> elements (and kid elements). with each <dept> element, create new instance of organisation , assign value of "operationalstatus" attribute operationalstatus property of organisation. (string) cast gracefully handle situation specified attribute not present. for legal start date, query on <startdate> children of <dept> element, taking first 1 has attribute "type" equal "legal". for operational start date, similar query number 3, except it's looking "operational". convert ienumerabale<t> result list calling .tolist() extension method.

this may not efficient, , doesn't cover properties have in original code, should @ to the lowest degree going in right direction. example, if wanted "primaryrole" attribute, you'd add together next line in new organisation() block:

orgprimaryrole = (string)x.attribute("primaryrole"),

if need info <deptroles> can to, it's little more involved.

if prefer query syntax on method syntax, this:

listorgdata = (from x in xdoc.root.elements("dept") select new { orgoperationalstatus = (string)x.attribute("operationalstatus"), orglegalstartdate = (from x1 in x.elements("startdate") (string)x1.attribute("type") == "legal" select (string)x1).first(), orgoperationalstartdate = (from x1 in x.elements("startdate") (string)x1.attribute("type") == "operational" select (string)x1).first() }).tolist();

c# asp.net xml linq-to-xml

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