java - StringUtils.countMatches words starting with a string? -

java - StringUtils.countMatches words starting with a string? -

i'm usingstringutils.countmatches count word frequencies, there way search text words starting-with characters?

example:

searching art in "artificial fine art in apartment" homecoming 3! need homecoming 2 words starting art only.

my solution replace \r , \n in text space , modify code be:

text = text.replaceall("(\r\n|\n)"," ").tolowercase(); searchword = " "+searchword.tolowercase(); stringutils.countmatches(text, searchword);

i tried next regex:

patternstring = "\\b(" + searchword.tolowercase().trim() + "([a-za-z]*))"; pattern = pattern.compile(patternstring); matcher = pattern.matcher(text.tolowercase());

questions: -does first solution create sense or there improve way this?

-is sec solution faster? i'm working big text files , decent number of search-words.

thanks

text = text.replaceall("(\r\n|\n)"," ").tolowercase(); searchword = " "+searchword.tolowercase(); string[] words = text.split(" "); int count = 0; for(string word : words) if(searchword.length() < word.length()) if(word.substring(word.length).equals(searchword)) count++;

loops provide same effect.

java frequency apache-stringutils