python 2.7 - How can I pass a .txt file as a function parameter -

python 2.7 - How can I pass a .txt file as a function parameter -

say have function reads .txt file , creates arrays based on columns of info within file. have right within function looks like:

data = open("some_file_name.txt","r")

but if want alter .txt file function reads have manually go code , type in new file name before running again. instead, how can pass file name function looks like:

my_function(/filepath/some_file_name.txt): info = open("specified_file_name.txt","r")

i think want

def my_function(filepath): info = open(filepath, "r") ...

and then

my_function("/filepath/some_file_name.txt")

or better:

def my_function(data): ...

and then

with open("/filepath/some_file_name.txt", "rb") data: my_function(data)

the latter version lets pass in file-like object my_function().

update: if want fancy , allow file names or file handles:

def my_func(data): if isinstance(data, basestring): open(data, 'rb') f: homecoming my_func(f) ...

function python-2.7 filepath