javascript - jQuery if condition for radio button name and value -



javascript - jQuery if condition for radio button name and value -

i have radio button like

<input type="radio" name="user-type" value="store"> <input type="radio" name="user-type" value="brand">

i tried writing jquery script like

if($("input[name=user-type]:checked").val()) == "brand"){ $(".showstore").hide(); $(".showbrand").show(); }

and tried

if($("input[name=user-type]:checked").val()) == "brand").click(function(){ $(".showstore").hide(); $(".showbrand").show(); });

and tried

if ( $("input[name=user-type]:radio").val() == "brand"){ $(".showstore").hide(); $(".showbrand").show(); }

none of these worked, correction appreciated. thanks.

update1

i tried in way , hide both

if($("input[name=user-type]:checked").val() == "brand"){ $(".showstore").hide(); $(".showbrand").show(); } else if($("input[name=user-type]:checked").val() == "store"){ $(".showstore").show(); $(".showbrand").hide(); }

try next code - listens click on radio name=user-type, , toggles based on radio button clicked.

$(function () { $('.showstore').hide(); $('.showbrand').hide(); $("input[name=user-type]:radio").click(function () { if ($('input[name=user-type]:checked').val() == "brand") { $('.showstore').hide(); $('.showbrand').show(); } else if ($('input[name=user-type]:checked').val() == "store") { $('.showstore').show(); $('.showbrand').hide(); } }); });

a working fiddle: http://jsfiddle.net/fpush/1/

javascript jquery

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