alternative replaceWith() jquery without losing second element -



alternative replaceWith() jquery without losing second element -

example

<script type="text/javascript"> $(document).ready(function () { $("#exp1").replacewith($("#exp2")); }); </script> <div class="exp1">example 1</div> <div class="exp2">example 2</div>

when utilize code, lost exp2 ( mean illustration 2 not showing ), display illustration 1 has been replace illustration 2.. how not lose , replace exp1 exp2, , displays result below

<div class="exp2">example 2</div> <div class="exp2">example 2</div>

please help me .. thanks

you should clone() element utilize replacewith method. need utilize class selector

use

$(document).ready(function () { $(".exp1").replacewith($(".exp2").clone()); });

demo

jquery replacewith

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