bash - awk/sed extract string from between patterns -



bash - awk/sed extract string from between patterns -

i know there has been few hundred forms of question asked on stackoverflow, can't seem find suitable reply question.

i'm trying parse through /etc/ldap.conf file on linux box can pick out description fields between (description= , ):

*-bash-3.2$ grep '^nss_base_passwd' /etc/ldap.conf

nss_base_passwd ou=people,dc=ca,dc=somecompany,dc=com?one?|(description=td_fi)(description=td_f6)(description=td_f6)(description=tri_142)(description=14_142)(description=rex5)(description=rex5)(description=1950)*

i'm looking extract these own list no duplicates:

td_fi td_f6 tri_142 14_142 rex5 1950

(or on 1 line proper delimiter)

i had played sed few hours couldn't work - i'm not exclusively sure how utilize global option.

you utilize grep -p option,

$ grep '^nss_base_passwd' /etc/ldap.conf | grep -op '(?<=description\=)[^)]*' | uniq td_fi td_f6 tri_142 14_142 rex5 1950

explanation:

a positive lookbehind used in grep print characters after description= upto next ) bracket. uniq command used remove duplicates.

bash awk sed grep pattern-matching

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